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  • 11-11-2022
  • Chemistry
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Given the thermochemical equations
X₂ + 3 Y₂ → 2XY3 ΔH1= -340kJ
X₂ + 2Z₂ → 2XZ₂ ΔH2= -170 kJ
2Y2 + Z2 → 2Y₂Z ΔH3= -260 kJ

Calculate the change in enthalpy for the reaction.

4XY3 +7Z₂ → 6Y₂Z + 4 XZ₂

ΔH= ____ kJ

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