The length of a rectangle is 15 less than its width, w. The perimeter, P, of the rectangle is, at most, 50. Write an inequality that can be used to find the longest possible width. P≥ 2(w-15) + 2w
P≤ (2l) + (2w)
P=2(w-15)+ 2w
P≤2(w-15) + 2w​