A particle is moving along a straight line and its velocity is given by v(t) = t^2e^(-t) feet per second after t seconds. What is the integral of t^2e^(-t)dv from 0 to 5?
A) 25e^(-5) - 2e^(-5) B) 25e^(-5) + 2e^(-5) C) -25e^(-5) + 2e^(-5) D) -25e^(-5) - 2e^(-5)
