sujeyribetanco3783 sujeyribetanco3783
  • 15-03-2024
  • Physics
contestada

Calculate the energy required to remove the least tightly neutron form .²⁰ (Ca⁴⁰).
Given that
Mass of . ²⁰ (Ca⁴⁰)=39.962589aμ
Mass of .²⁰ (Ca³⁹)= 38.970691aμ
Mass of neutron = 1.008665aμ

Respuesta :

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