loveabledee1954
loveabledee1954 loveabledee1954
  • 15-04-2024
  • Mathematics
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Given two functions j(x)=−3x 2 and k(x)=3 4x , what is the function rule for (kj)(x) ? Responses (kj)(x)=−12x2 x−6 ( k j ) ( x ) = − 12 x 2 x − 6 (kj)(x)=−12x2 18x 6 ( k j ) ( x ) = − 12 x 2 18 x 6 (kj)(x)=12x2−18x−6 ( k j ) ( x ) = 12 x 2 − 18 x − 6 (kj)(x)=−12x2−x 6

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