Calculate the volume in liters of a ×4.3910−5/moll mercury(ii) iodide solution that contains 500.mg of mercury(ii) iodide hgi2 . round your answer to 3 significant digits.
the molarity of the solution is 4.39 x 10⁻⁵ mol/L molarity is the number of moles of solute in 1 L of solution in this instance there are 4.39 x 10⁻⁵ mol of HgI₂ in 1 L solution the mass of HgI₂ in 1 L - 4.39 x 10⁻⁵ mol x 454.4 g/mol = 19.9 mg if 19.9 mg are in 1 L then 500.0 mg are in - 500.0 mg / 19.9 mg/L = 25.1 L therefore volume is 25.1 L
