kynasworldp585gk
kynasworldp585gk
12-05-2018
Mathematics
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How to do this I’m lost
Respuesta :
gmany
gmany
12-05-2018
[tex]y=9-x^2\ \ \ |-9\\\\y-9=-x^2\ \ \ \ |change\ the\ signs\\\\x^2=9-y\to x=\sqrt{9-y}[/tex]
[tex]We\ have\ y^{-1}=\sqrt{9-x}\\\\D:\\9-x\geq0\to x\leq9\\\\x\in\left(-\infty;\ 9\right>[/tex]
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