we can use the dilution equation to find the new concentration of the solution c1v1 = c2v2 where c1 is concentration and v1 is volume of the concentrated solution c2 is concentration and v2 is volume of the diluted solution prepared c1 - 4 M v1 - 2 L of the concentrated solution is taken to be diluted v2 - final volume of diluted solution - 2 L + 6 L = 8 L substituting these values 4 M x 2 L = C x 8 L C = 1 M new concentration of the diluted solution is 1 M
