Respuesta :

Matheng
See the attached figure.
f(x)=-2x−3 ⇒⇒ black graph ⇒⇒ range = R


g(x)=-2|x+3|−3 ⇒⇒ red graph ⇒⇒ range = {y∣y ≤ -3}


h(x)=-2(x−4)²+3 ⇒⇒ blue graph ⇒⇒ range = {y∣y ≤ 3}


j(x)=-2x³+3x²+x−1 ⇒⇒ green graph ⇒⇒ range = R


∴ The function which has a range of {y∣y ≤ 3} is h(x)=-2(x−4)²+3

   Which is the third choice


Ver imagen Matheng

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