anaguzman
anaguzman anaguzman
  • 15-05-2018
  • Mathematics
contestada

help please, i don't understand it!!!!

help please i dont understand it class=

Respuesta :

gmany
gmany gmany
  • 15-05-2018
[tex]V=\dfrac{4}{3}\pi r^3\ \ \ |\cdot\dfrac{3}{4}\\\\\pi r^3=\dfrac{3V}{4}\ \ \ \ |:\pi\\\\r^3=\dfrac{3V}{4\pi}\ \ \ |:r\\\\r^2=\dfrac{3V}{4\pi r^2}[/tex]

Substitute to S.A.

[tex]S.A.=4\pi r^2=4\pi\cdot\dfrac{3V}{4\pi r^2}=\dfrac{3V}{r}[/tex]

[tex]\dfrac{S.A.}{V}=\dfrac{4\pi r^2}{\frac{4}{3}\pi r^3}=\dfrac{3}{r}[/tex]

[tex]\dfrac{S.A.}{V}=1\to\dfrac{3}{r}=1\to r=3[/tex]

Answer: B
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