Respuesta :
they rearrange to
y > -(2/3)x + 2 and
y< -(3/2)x + 3
the equations of the lines have negative slopes and y intercepts of 2 and 3 and second equation is steeper than the first so we could try a point where y = 4 and and say a negative x value of -1 and see if they fit the inequalities
2(-1) + 3(4) = 10 > 6
and
3(-2) + 2(4) = 2 < 6
So one point would be (-1, 4)
y > -(2/3)x + 2 and
y< -(3/2)x + 3
the equations of the lines have negative slopes and y intercepts of 2 and 3 and second equation is steeper than the first so we could try a point where y = 4 and and say a negative x value of -1 and see if they fit the inequalities
2(-1) + 3(4) = 10 > 6
and
3(-2) + 2(4) = 2 < 6
So one point would be (-1, 4)
