lescoto2321 lescoto2321
  • 12-06-2018
  • Chemistry
contestada

If 0.97 moles of BaCl2 are dissolved in enough water to make a 1.2 liter soulution, what is the resulting molarity

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JoshEast
JoshEast JoshEast
  • 16-06-2018
         If    1.2 L of solution contains 0.97 mol
then let     1 L of solution contain  x   mol
     
       ⇒ (1.2 L) x  = (0.97 mol) (1 L)

                      x  = (0.97 mol · L)  ÷  (1.2 L)

                      x  = 0.8083 mol

Thus the molarity of the Barium Chloride solution is 0.808 mol / L   OR  0.808 mol/dm³. 

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