Respuesta :

Edufirst
Answer: - 3.91 °C


Explanation:

1) The depression of the freezing point of a solution is a colligative property and its value is:


ΔTf = m × Kf × i


2) i is the Van't Hoof constant ans for non ionic solutes is 1.


3) m is the molality


m = 2.1 m


3) ΔTf = 2.1 m × 1 × 1.86 °C / mol = 3.91°C.


5) Freezing poin (temperature)

Tf = 0° - 3.91 °C = - 3.91°C

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