If you solve d = rt for t, you have t = d/r. If we have values for d and r we will fill them into that equation and divide. [tex] \frac{545.79m}{48.3 \frac{m}{h} } [/tex]. Setting that up so the meters cancel as they should looks like this: [tex]545.79m* \frac{h}{48.3m} [/tex] lets us divide as we need to and at the same time cancel out the distance, leaving us time in hours. The t value then is 11.3 hours.
