pdiddyy7171 pdiddyy7171
  • 13-06-2018
  • Mathematics
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What is the vertical asymptote(s) for y=x^2+2x/x^2+5x-6?

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Luv2Teach
Luv2Teach Luv2Teach
  • 13-06-2018
The vertical asymptotes exist where the denominator goes to 0.  That means we have to factor it to find the trouble spots.  [tex] x^{2} +5x-6[/tex] factors easily into (x - 1)(x + 6), telling us that x = 1 and x = -6 by the zero product property.  Therefore, the vertical asymptotes for this rational function are at x = 1 and x = -6
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