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dahianaharmoniz1
Your answer should be 16/9
[tex]\bf \left( \cfrac{64}{27} \right)^{\frac{2}{3}}\implies \left( \cfrac{4^3}{3^3} \right)^{\frac{2}{3}}\implies \left( \cfrac{4^{3\cdot \frac{2}{3}}}{3^{3\cdot \frac{2}{3}}} \right)\implies \cfrac{4^2}{3^2}\implies \cfrac{16}{9}[/tex]

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