Piglovers101
Piglovers101
14-06-2018
Mathematics
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Can anyone help me on this please?
Respuesta :
gmany
gmany
14-06-2018
[tex]\dfrac{4a^3b^2+2a^2b^2+3ab}{ab}=\dfrac{4a^3b^2}{ab}+\dfrac{2a^2b^2}{ab}+\dfrac{3ab}{ab}=4a^2b+2ab+3[/tex]
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