bbygirlmaddie
bbygirlmaddie bbygirlmaddie
  • 15-06-2018
  • Mathematics
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  • 15-06-2018
[tex]\dfrac{3}{\sqrt7}=\dfrac{3\cdot\sqrt7}{\sqrt7\cdot\sqrt7}=\boxed{\dfrac{3\sqrt7}{7}}\\\\\\\text{Used:}\ \sqrt{a}\cdot\sqrt{a}=a[/tex]
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