Respuesta :

jcherry99
Short Answer: pi/6 5pi/6 pi/2 3pi/2
Step One
Pull cos(theta) our of the brackets
cos(theta)*(sin(theta) - 1/2) = 0         Do not divide by cos(theta)

Step Two
Identify the sources of the solution
.
You have 2 sources of solutions for this
The first is cos(theta)

source 1
cos(theta) = 0 
Theta can have 2 values 
pi/2 and (3/2 pi)

Source 2
You also have another source
sin(theta - 1/ 2 = 0
sin(theta) = 1/2
Theta can have 2 values One in quadrant 1 and one in quadrant 2

Quadrant 1
Theta = 30o = 30/180 * pi = pi/6

Quadrant 2
Theta = 180 - 30 = 150o = 150o/180 * pi = (5/6) pi

Otras preguntas