[tex]y=mx+b[/tex]
m - a slope
b - a y-intercept
[tex]b=-\dfrac{13}{3}[/tex]
therefore [tex]y=mx-\dfrac{13}{3}[/tex]
Put the values of the coordinates of the point (-5; -1) to the equation
[tex]x=-5;\ y=-1\\\\-1=m\cdot(-5)-\dfrac{13}{3}\ \ \ |\cdot3\\\\-3=-15m-13\ \ \ |+13\\\\10m=-15\ \ \ |:10\\\\m=\dfrac{-15}{10}\\\\m=-\dfrac{3}{2}[/tex]
Answer: [tex]y=-\dfrac{3}{2}x-\dfrac{13}{3}[/tex]
