lllleklfkhlsdf1811 lllleklfkhlsdf1811
  • 13-07-2018
  • Chemistry
contestada

How many grams of water do you have to decompose if you want to prepare 34.7 g of oxygen?

Respuesta :

evgeniylevi
evgeniylevi evgeniylevi
  • 13-07-2018

Try this solution:

The equation of the reaction is:

2H₂O⇒2H₂↑+O₂↑ where m(O₂)=34.7gr.


M(O₂)=16*2=32 (gr./mol);

ν(O₂)=m(O₂)/M(O₂)=34.7/32=1.084375 (mol).


According to the equation of the reaction ν(H₂O)=2ν(O₂)=2*1.084375=2.16875 (mol);

M(H₂O)=2+16=18 (gr./mol).

m(H₂O)=M(H₂O)*ν(H₂O)=18*2.16875=39.0375 gr.


Answer: 39.0375 gr.

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