braz50 braz50
  • 13-08-2018
  • Mathematics
contestada

How do I solve this problem

How do I solve this problem class=

Respuesta :

jdoe0001 jdoe0001
  • 13-08-2018

[tex] \bf 9p>63\implies p>\cfrac{63}{9}\implies \boxed{p>7}\\\\\\\cfrac{p}{3}\le 2\implies \boxed{p\le 6} [/tex]


check the picture below.

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gmany
gmany gmany
  • 13-08-2018

[tex]9p > 63\ \ \ \ |:9\\\\p > 7\\--------------\\\\\dfrac{p}{3}\leq2\ \ \ \ |\cdot3\\\\p\leq6[/tex]

Answer:

On the picture.

[tex]p\in(-\infty;\ 6]\ \cup\ (7,\ \infty)[/tex]

Ver imagen gmany
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