waynelisa waynelisa
  • 15-09-2018
  • Mathematics
contestada

Find an equation of the circle that satisfies the given conditions. Center at the origin; passes through (1,6)

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jimrgrant1 jimrgrant1
  • 15-09-2018

x² + y² = 37

The equation of a circle centred at the origin is.

x² + y² = r² ( where r is the radius)

The radius can be calculated using the distance formula

r = √(x₂ - x₁ )² + (y₂ - y₁)²

where (x₁ , y₁) =(0,0) and (x₂ ,y₂) = (1 ,6)

r = √(1 - 0)² +(6 -0)² = √1 + 36 =√37⇒ r² = (√37)² = 37

x² + y² = 37  is the equation of the circle





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