Zeretric Zeretric
  • 12-10-2018
  • Mathematics
contestada

3/2(b + 1) = 3..........

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jimrgrant1 jimrgrant1
  • 12-10-2018

b = - [tex]\frac{1}{2}[/tex]

multiply both sides by 2(b + 1) to eliminate the fraction

3 = 3× 2(b + 1)

3 = 6(b + 1) = 6b + 6  ( subtract 6 from both sides )

- 3 = 6b ( divide both sides by 6 )

b = - [tex]\frac{3}{6}[/tex] = - [tex]\frac{1}{2}[/tex]


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