AgNO3(aq) + NaCl(aq) = AgCl(s) + NaNO3
MWt AgNO3 = 169.87; AgCl = 143.32
From the eqn 169.87 g of AgNO3 yield 143.32 g of AgCl
1.000g of AgNO3 yield 143.32/169.87 g of AgCl
Hence 4.27 g will yield (143.32/169.87)×4.27 g of AgCl
= 3.60 g of AgCl which is the theoretical yield.
% yield = (2.56/3.60)× 100 = 71.1%
A skilled chemist (e.g., Marie Curie) would get close to 100%.
