gracerice11 gracerice11
  • 15-10-2018
  • Mathematics
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What is the zeros and graph of f(x)=1/2(x+5)(x+1)(x-2)

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Аноним Аноним
  • 15-10-2018

When you write a polynomial in the form

[tex] p(x) = A(x-x_1)(x-x_2)\ldots(x-x_n) [/tex]

You know that you have a polynomial of degree [tex] n [/tex], which crosses the x axis at [tex] x_1,\ x_2,\ldots,x_n [/tex]

So, in your case, you have a cubic which crosses the x axis at x=-5, x=-1 and x=2.

Moreover, since A=1/2 is positive, the end behaviour of the cubic is preserved, i.e.

[tex] \displaystyle \lim_{x\to\pm\infty}p(x)=\pm\infty [/tex]

This is all the information you need to sketch a first draft of the graph.

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