The point-slope form:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-1, 3) and (2, -2). Substitute:
[tex]m=\dfrac{-2-3}{2-(-1)}=\dfrac{-5}{2+1}=-\dfrac{5}{3}\\\\y-3=-\dfrac{5}{3}(x-(-1))\\\\\boxed{y-3=-\dfrac{5}{3}(x+1)}[/tex]
