COOLDUDE3378 COOLDUDE3378
  • 12-11-2018
  • Mathematics
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How many five​-digit odd numbers are possible if the leftmost digit cannot be​ zero?

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chisnau chisnau
  • 13-11-2018

As given , leftmost or the First digit cannot be zero,

So, there are 9 choices for the first digit: 1,2,3,4,5,6,7,8,9 Excluding 0


And the second, third and fourth digits you are choosing from 10 digits: 0,1,2,3,4,5,6,7,8,9


Similarly, the fifth digit you will be choosing from 5 digits: 1,3,5,7,9 (because Numbers has to be odd)


= [tex]9\times10\times10\times10\times5[/tex] = 45000

Hence, 45000 five-digit odd numbers are possible.

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