Answer:
a ≤ 0
Step-by-step explanation:
[tex]-\dfrac{1}{2}a-4\geq-4\qquad\text{add 4 to both sides}\\\\-\dfrac{1}{2}a-4+4\geq-4+4\\\\-\dfrac{1}{2}a\geq0\qquad\text{change the signs}\\\\\dfrac{1}{2}a\leq0\qquad\text{multiply both sides by 2}\\\\2\!\!\!\!\diagup^1\cdot\dfrac{1}{2\!\!\!\!\diagup_1}a\leq(2)(0)\\\\a\leq0[/tex]
