Use the 30-60-90 triangle.
Tan is opposite over adjacent.
[tex] \frac{1}{ \sqrt{3} } [/tex]
Square roots cannot be on the bottom.
[tex] \frac{1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } [/tex]
The bottom cancel out the square root bar.
Your answer is:
[tex] \frac{ \sqrt{3} }{3} [/tex]
(It's best to memorize the 30-60-90 and the 45-45-90 triangles during trigonometry. It helps a lot.)
Hope this helps!
:)
