Kayla1113 Kayla1113
  • 13-12-2018
  • Mathematics
contestada

what is the center and radius of the equation (x-8)^2 +(y+6)^2=13

Respuesta :

jimrgrant1 jimrgrant1
  • 13-12-2018

Answer:

see explanation

Step-by-step explanation:

the equation of a circle in standard form is

(x - a)² + (y - b)² = r²

where (a, b) are the coordinates of the centre and r is the radius

(x - 8)² + (y + 6)² = 13 is in this form

with centre = (8, - 6) and r = [tex]\sqrt{13}[/tex]



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