nb644768 nb644768
  • 15-12-2018
  • Mathematics
contestada

Solve -3n + 4 ≥ -8.
n ≥ 4
n ≤ 4
n ≥ -4
n ≤ -4

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 15-12-2018

Answer:

n ≤ 4

Step-by-step explanation:

-3n + 4 ≥ -8.

Subtract 4 from each side

-3n + 4-4   ≥ -8-4

-3n   ≥ -12

Divide by -3 on each side, remembering to flip the inequality

-3n/-3 ≤ -12/-3

n≤4

Answer Link
itmye84 itmye84
  • 15-12-2018

-3n + 4 ≥ -8         Subtract 4 on both sides

-3n + 4 - 4 ≥ - 8 - 4

-3n ≥ - 12        Divide -3 on both sides to get "n" by itself

n ≤ 4    (when you multiply or divide a negative number on both sides of the inequality, you flip the sign(< > ≤ ≥))


The 2nd option is your answer


Answer Link

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