ciarakelly245 ciarakelly245

12-01-2019
Mathematics

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Please help me answer just Q19 all parts of Q19 n the photo

Please show all your workings to how you got your answers!

Please help me answer just Q19 all parts of Q19 n the photo Please show all your workings to how you got your answers class=

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erickannangara erickannangara

12-01-2019

Answer:

i)37 degrees

ii)BC=6.02cm,DC=4.02cm

Step-by-step explanation:

i)Angle BAC =18o degrees-(90 degrees + 53 degrees)

=37 degrees

ii)sin 37=Opp./Hyp.=BC/AB

0.602=opp/10

BC=6.02cm

DC=6.02cm-2cm=4.02cm

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