sneky0snek sneky0snek
  • 13-01-2019
  • Mathematics
contestada

find the vertex of this parabola y=-5x^2-10x-15

Respuesta :

jimrgrant1 jimrgrant1
  • 13-01-2019

Answer:

vertex = (- 1, - 10 )

Step-by-step explanation:

given the equation of a parabola in standard form

y = ax² + bx + c : a ≠ 0

Then the x-coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = - 5x² - 10x - 15 is in standard form

with a = - 5, b = - 10 and c = - 15, hence

[tex]x_{vertex}[/tex] = - [tex]\frac{-10}{-10}[/tex] = - 1

substitute x = - 1 into the equation for y

y = - 5(- 1)² - 10(- 1) - 15 = - 5 + 10 - 15 = - 10

vertex = (- 1, - 10 )


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