Answer:
(3·x^2 - 2·x)·(2·x^2 + 3·x - 1)
= 3·x^2·2·x^2 + 3·x^2·3·x - 3·x^2·1 - 2·x·2·x^2 - 2·x·3·x + 2·x·1
= 6·x^4 + 9·x^3 - 3·x^2 - 4·x^3 - 6·x^2 + 2·x
= 6·x^4 + 5·x^3 - 9·x^2 + 2·x
