Answer:
[tex]8y^3+6y^2-29y+15[/tex]
Step-by-step explanation:
[tex](4y-3)(2y^2 +3y-5)[/tex]
multiply 4y inside the parenthesis
[tex](4y)(2y^2 +3y-5)=8y^3+12y^2-20y[/tex]
Now we multiply -3 inside the second parenthesis
[tex](-3)(2y^2 +3y-5)=-6y^2-9y+15[/tex]
[tex](4y-3)(2y^2 +3y-5)[/tex]
[tex]8y^3+12y^2-20y-6y^2-9y+15[/tex]
Now we combine like terms
[tex]8y^3+6y^2-29y+15[/tex]
