Answer:
[tex]sin(\theta)=\frac{7}{\sqrt{58} }[/tex]
Step-by-step explanation:
We are given
the terminal side of θ passes through the point (-3,7)
so,
x=-3
y=7
Since, x-value is negative and y-value is positive
It means that angle lies in second quadrant
Firstly, we will draw triangle
sin is always positive
so, we get
[tex]sin(\theta)=\frac{7}{\sqrt{58} }[/tex]
