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  • 11-02-2019
  • Mathematics
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Sec^2 theta/tan theta = sec theta x csc theta

Respuesta :

jimrgrant1 jimrgrant1
  • 11-02-2019

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

• tan x = [tex]\frac{sinx}{cosx}[/tex]

• sec x = [tex]\frac{1}{cosx}[/tex], csc x = [tex]\frac{1}{sinx}[/tex]

Consider the left side with x = Θ

[tex]\frac{sec^2x}{tanx}[/tex]

=[tex]\frac{1/cos^2x}{\frac{sinx}{cosx} }[/tex]

= [tex]\frac{1}{cos^2x}[/tex] × [tex]\frac{cosx}{sinx}[/tex]

= [tex]\frac{1}{cosxsinx}[/tex]

= [tex]\frac{1}{cosx}[/tex] × [tex]\frac{1}{sinx}[/tex]

= secxcscx = right side ⇒ verified


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