emilysontay
emilysontay emilysontay
  • 11-02-2019
  • Mathematics
contestada

1.) p^2+14p-38=0
what the vertex?

Respuesta :

jimrgrant1 jimrgrant1
  • 11-02-2019

Answer:

vertex = (- 7, - 87)

Step-by-step explanation:

given a parabola in standard form : ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

p² + 14p - 38 is in standard form

with a = 1, b = 14, c = - 38, hence

[tex]x_{vertex }[/tex] = - [tex]\frac{14}{2}[/tex] = -7

substitute x = - 7 into the equation for corresponding value of y

y = (- 7)² + 14(- 7) - 38 = 49 - 98 - 38 - - 87

vertex = (- 7, - 87)


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