The correct answer is 4.6 liters of O₂ gas is formed.
The concentration of CO₂ given is 4.60 liters
CO₂ (g) ↔ C (s) + O₂ (g)
Since 1 mole of CO₂ give 1 mole of O₂ upon reaction
So mole of O₂ produced = mole of CO₂
At STP, 1 mole gas contain 22.4 liter volume
So, mole of CO₂ = 4.6 / 22.4 = 0.20535
Mole of O₂ formed = mole of CO₂ = 0.20535
Volume of O₂ = 0.20535 × 22.4
= 4.6 liters
Therefore, 4.6 liters of O₂ (g) is formed.
