Aidanme25 Aidanme25

12-02-2019
Mathematics

contestada

What the vertex and AOS if the equation is y=(x-2)^2-2

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Аноним Аноним

12-02-2019

Answer:

See below.

Step-by-step explanation:

For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.

So for y = (x-2)^2 - 2,

the vertex is (2, -2) and the axis of symmetry is x = 2.

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