markarianlaura1
markarianlaura1 markarianlaura1
  • 16-02-2019
  • Mathematics
contestada

Find three consecutive odd integers such that the square of the second decreased by four times the first is seven more than six times the third.

please help

Respuesta :

mathecoach
mathecoach mathecoach
  • 16-02-2019

Answer:

x, x+2, x+4

(x+2)^2 - 4(x) = 6(x + 4) + 7

x^2 + 4x + 4 - 4x = 6x + 24 + 7

x^2 - 6x - 27 = 0

x = 9 (∨ x = -3)

The three numbers are

9, 11, 13

but it could be also

-3, -1, 1

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