Answer:
J 56
Step-by-step explanation:
The area of the figure is the large square x^2 minus the small square y^2
The area is x^2 -y^2 = 52
Since x and y are integers the of the squares must be 52
x^2 = y^2 +52
We know that it must be fairly large
Let y = 12
x^2 = 12^2 +52
x^2 = 144+52
x^2 = 196
x=14
The perimeter is the sum of the 4 sides
P = x+x + (x-y) +y+y + (x-y)
Combining like terms
P = 4x
P = 4(14)
P = 56
