NotYourStudent
NotYourStudent NotYourStudent
  • 11-03-2019
  • Mathematics
contestada

PLEASE HELP
Solve the equation, x2 - 2x - 8 = 0 by completing the square .

a. x = 4 or x = -2

b. x = 4 or x = 2

c. x = -4 or x = -2

d. x = -4 or x = 2

Respuesta :

MrsStrong
MrsStrong MrsStrong
  • 14-03-2019

Answer:

A

Step-by-step explanation:

Completing the square requires a quadratic in [tex]ax^2+bx=c[/tex] form. Once in this form, calculate [tex](\frac{b}{2})^2[/tex].

Here x2 - 2x - 8 = 0 converts to x2 - 2x = 8. So b = -2.

[tex](\frac{b}{2})^2=(\frac{-2}{2})^2=1[/tex]

Add 1 to both sides.

x2 - 2x + 1 = 8 + 1

(x -1)^2 = 9

Square root both sides.

x-1 = 3                        x - 1 = -3

x = 4                           x = -2

This is the solution.

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