Answer:
[tex]x_1=9\\x_2=5[/tex]
Step-by-step explanation:
To solve this problem, you must:
- Subtract 7 from both sides of the equation:
[tex]x^{2}-14x+52-7=7-7\\x^{2}-14x+45=0[/tex]
- Now, you can factor it. Choose two numbers whose sum -14 and whose product is 45. These numbers would be -9 and -5. Therefore, you obtain the following solution:
[tex](x-9)(x-5)=0\\\\x_1=9\\x_2=5[/tex]
