Answer:
[tex]653.33gH_3PO_4[/tex]
Explanation:
Hello,
In this case, by considering the given chemical reaction and the molar mass for phosphoric acid and the 4 to 6 relationship between phosphoric acid and water respectively, the required grams are result:
[tex]10.0molH_2O*\frac{4molH_3PO_4}{6molH_2O} *\frac{98gH_3PO_4}{1molH_3PO_4} =653.33gH_3PO_4[/tex]
Best regards.
