rupinderkhehraz rupinderkhehraz
  • 14-03-2019
  • Mathematics
contestada

write expression as one circular function ​

write expression as one circular function class=

Respuesta :

mathstudent55
mathstudent55 mathstudent55
  • 14-03-2019

Answer:

[tex] \cos^2 x [/tex]

Step-by-step explanation:

[tex] \dfrac{\cos^2 x \sin^2 x}{\tan^2 x(1 - \sin^2 x)} = [/tex]

[tex] = \dfrac{\cancel{\cos^2 x} \sin^2 x}{\tan^2 x\cancel{\cos^2 x}} [/tex]

[tex] = \dfrac{\sin^2 x}{\tan^2 x} [/tex]

[tex] = \dfrac{\sin^2 x}{\dfrac{\sin^2 x}{\cos^2 x}} [/tex]

[tex] = \sin^2 x \times \dfrac{\cos^2 x}{\sin^2 x} [/tex]

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