Answer:
For both figures [tex]A=4+2+2+1=9\ units^{2}[/tex]
Step-by-step explanation:
we know that
The area for both composite figures is equal to the area of a square plus the area of two isosceles right triangles plus the area of a smaller isosceles triangle
so
Area of the square
[tex]A=2^{2}=4\ units^{2}[/tex]
Area of the isosceles right triangle
[tex]A=(1/2)(2)(2)=2\ units^{2}[/tex]
Area of the smaller isosceles triangle
[tex]A=(1/2)(2)(1)=1\ units^{2}[/tex]
The area of the composite figure is
[tex]A=4+2+2+1=9\ units^{2}[/tex]
