For this case we have that Hooke's law is dadapor:
[tex]F = kx[/tex]
Where:
F: It's the strength
x: It is the deformation when applying force
k: It is the constant of proportionality
They tell us that:
[tex]F = 500 \ N\\x = 0.5 \ m[/tex]
We must find k.
[tex]k = \frac {F} {x}\\k = \frac {500} {0.5}\\k = 1000 \frac {N} {m}[/tex]
Answer:
[tex]k = 1000 \frac {N} {m}[/tex]
