Answer: [tex]\bold{C)\quad -\dfrac{1}{2}}[/tex]
Step-by-step explanation:
[tex]\dfrac{x+2}{15}=\dfrac{x+1}{5}\\\\\\\underline{\text{Multiply both sides by the LCD (15) to eliminate the denominator:}}\\x+2=3(x+1)\\x+2=3x+3\\.\quad \ 2=2x+3\\.\quad -1=2x\\\\.\quad \large\boxed{-\dfrac{1}{2}=x}[/tex]
